Question

sir trigonometrie formula explain please​

Answer 1

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Trigonometry Formulas :-

• •SinA = P / H
• •CosA = B / H
• •TanA = P / B
• •CotA = B / P
• •CosecA = H / P
• •SecA = H/B
• •Sin2A + Cos2A = 1
• •Tan2A + 1 = Sec2A
• •Cot2A + 1 = Cosec2A
• • TanA = SinA / CosA
• • CotA = CosA / SinA
• • CosecA = 1 / SinA
• • SecA = 1 / CosA
• • Sin (A +B) =SinA . CosB + CosA . SinB
• • Sin (A – B) = SinA . CosB – CosA . SinB
• • Cos (A + B) = CosA . CosB – SinA . SinB
• • Cos (A – B) = CosA. CosB + SinA . SinB
• • Tan (A + B) = TanA + TanB / 1 – TanA . TanB
• • Tan (A – B) = TanA –TanB / 1 + TanA . TanB
• • Sin ( A + B) . Sin (A – B) = Sin2A – Sin2B = Cos2B – Cos2A
• • Cos (A + B) . Cos (A – B) = Cos2A – Sin2B = Cos2B – Sin2A
• • Sin2A = 2 . SinA . CosA = 2 . TanA / (1 + Tan2A)

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Answer 2

Answer:

Trigonometry Formulas :-

•SinA = P / H

•CosA = B / H

•TanA = P / B

•CotA = B / P

•CosecA = H / P

•SecA = H/B

•Sin2A + Cos2A = 1

•Tan2A + 1 = Sec2A

•Cot2A + 1 = Cosec2A

• TanA = SinA / CosA

• CotA = CosA / SinA

• CosecA = 1 / SinA

• SecA = 1 / CosA

• Sin (A +B) =SinA . CosB + CosA . SinB

• Sin (A – B) = SinA . CosB – CosA . SinB

• Cos (A + B) = CosA . CosB – SinA . SinB

• Cos (A – B) = CosA. CosB + SinA . SinB

• Tan (A + B) = TanA + TanB / 1 – TanA . TanB

• Tan (A – B) = TanA –TanB / 1 + TanA . TanB

• Sin ( A + B) . Sin (A – B) = Sin2A – Sin2B = Cos2B – Cos2A

• Cos (A + B) . Cos (A – B) = Cos2A – Sin2B = Cos2B – Sin2A

• Sin2A = 2 . SinA . CosA = 2 . TanA / (1 + Tan2A)

hope this helps ❤️