Question

Sir you have solve a question of quad eq that abx² +acx+b(bx+c) in that ques where u have found x2 there one b should b in +ve n other should b in -ve plz c that n correct it

Answer 1

abx^2 + (b^2 - ac)x - bc =0

D = b^2 - 4ac

= [ b^2 - ac ]^2 - 4 * ab * -bc

= b^4 - 2b^2 ac + (ac)^2 + 4ab^2 c

= b^4 + 2ab^2c + (ac)^2

= [ b^2 + ac ]^2

x = [ - ( b^2 - ac ) +/- b^2 + ac ] / 2ab

= [ - b^2 + ac +/- b^2 + ac ] / 2ab

= [ - b^2 + ac + b^2 +ac ] / 2ab ,

[ - b^2+ac - ( b^2 + ac ) ] / 2ab

= 2ac / 2ab , -2b^2 /2ab

= c / b , -b / a