Question

sirju runs 5 times around a rectangular park 42m in lenght and 32 in breadth, whereas anuj runs around a square fielf of side 65 m for 5 times. who covers more distance and by how much?
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Answer 1

Answer:

SIRJU -

no. of times he runs = 5

length of rectangular park = 42m

breadth = 32m

Then, distance covered = 5 × perimeter

                                        = 5 × 2( l+b )

                                        = 5 × 2 ( 42+32)

                                        = 720m

ANUJ -

no. of times he runs = 5

length of any side of square field = 65m

Then, total distance = 5 × perimeter of square

                                 = 5 × 4s

                                 = 5 ×  260

                                 =  1300m

1300-720 =  580m

Therefore,

Anuj runs more than Sirju by 580m