Sis theta /1+ cos theta +1+cos theta /sin theta
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Answer:
2cosecθ
Step-by-step explanation:
sinθ/1+cosθ +1+cosθ/sinθ
= cross multiply, sin²θ+(1+cosθ)(1+cosθ)/sinθ(1+cosθ)
=sin²θ +cos²θ=1
∴ sin²θ +1+cosθ+cosθ+cos²θ/sinθ(1+cosθ)
=1+1+2cosθ/sinθ(1+cosθ)
=2+2cosθ/sinθ(1+cosθ)
=2(1+cosθ)/sinθ(1+cosθ) *1+cosθ and 1+cosθ wl get cancelled*
2(1/sinθ)
=2cosecθ
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