Math, asked by chetnasoni789, 9 months ago

Sita and gita can do a work in 20 days and 25 days respectively both begin together but after a few days Sita leaves.then gita finishes the remaining work in 10 days.after how many days did sita leaves

Answers

Answered by WafflesGoesBrainy
0

Answer:1.11 days

Step-by-step explanation:
time taken by Gita to do work = 20 days
time taken by Sita to do work = 25 days

work done by Gita in 1 day = 1/20
work done by Sita in 1 day = 1/25


work done done by both of them together = 1/20 + 1/25 = 9/100

therefore, time taken for them to do work together = reciprocal of 9/100 = 100/9 = 11.11 days = 11 days

work done by Sita alone = 10 days
thus no of days they did work together = 11 - 10 = 1 day

therefore Gita leaves after 1 day

Answered by GulabLachman
0

As per the given question, Sita left after 20/3 days

Given:

Time taken by Gita to do work = 20 days

Time taken by Sita to do work = 25 days

To Find:

After how many days did Sita leaves

Solution:

Let Sita and Geeta work together for days = x

Work done by Gita in 1 day = 1/20

Work done by Sita in 1 day = 1/25

Since Gita alone works for 10 days,

Therefore -

1/25 x 10

= 10/25

= 2/5

Remaining work -

= 1 - 2/5

= 3/5

Calculating the total number of days of both -

= 3/5 = x ( 1/10 + 1/25)

= 3/5 = x (35/250)

x = 20/3

Answer: As per the given question, Sita left after 20/3 days

#SPJ3

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