sita has pens &pencils which togother are 40 in number .if she had 5 more pencils & 5less pens, the number of pencil would have become 4 times the number of pens .find the original number of pens and pencils with sita
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Let the number of pens be "x"
Let the number of pencils be"y"
According to the question,
x+y = 40
5 more pencils means = y+5
5 less pens means = x-5
Now,
x-5+y+5 = 4 (number of pens) = 4x
⇒ x-y = 4x
⇒ -y = 3x
⇒ y = -3x -----------------------1
substitute 1 in the first equation
x+y = 40
⇒x -3x = 40
⇒-2x = 40
⇒ x = 20
∴ the number of pens with sita are 20.
substitute the value of "x" in 1 we get,
y = -3(x)
⇒ y = -3(20)
⇒ y = -60
∴ there were 60 pencils with sita and 20 pens.
Thank You......!!!!!!!!!
Mark as brainliest if helpful...
Yours, Jahnavi.
Let the number of pencils be"y"
According to the question,
x+y = 40
5 more pencils means = y+5
5 less pens means = x-5
Now,
x-5+y+5 = 4 (number of pens) = 4x
⇒ x-y = 4x
⇒ -y = 3x
⇒ y = -3x -----------------------1
substitute 1 in the first equation
x+y = 40
⇒x -3x = 40
⇒-2x = 40
⇒ x = 20
∴ the number of pens with sita are 20.
substitute the value of "x" in 1 we get,
y = -3(x)
⇒ y = -3(20)
⇒ y = -60
∴ there were 60 pencils with sita and 20 pens.
Thank You......!!!!!!!!!
Mark as brainliest if helpful...
Yours, Jahnavi.
app2:
wrong answer you
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