Math, asked by kannamma310, 1 year ago

Sivamani is attending an interview for a job and the company gave two offers to him.
Offer A: ₹20,000 to start with followed by a guaranteed annual increase of 6% for the
first 5 years.
Offer B: ₹22,000 to start with followed by a guaranteed annual increase of 3% for the
first 5 years.
What is his salary in the 4th year with respect to the offers A and B?​

Answers

Answered by parth545
13

Answer:

a=6000

b=3960

Step-by-step explanation:

SI=20000*6*5/100

=22000*3*6/100

Answered by AneesKakar
5

Answer:

The amount of money that he will get from both the companies will be.

From the company A he will get:-

For first year the salary will be 20000 while in the next year it will be 20000+6% of 20000 = 21200 for the third year 21200 + 6%of 21200 = 22472 and for the fourth year it will be 23820.32 thus from company A he will get 23,820 in the end of fourth year.

From company B he will get:-

For first year the salary will be 22000 while in the next year it will be 22000+6% of 22000 = 21320 for the third year 21320 + 6%of 21320 = 22599.2 and for the fourth year it will be 23955.15 thus from company B he will get 23955.15 in the end of fourth year.

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