Six 1 µF capacitors are so arranged that their equivalent capacitance is 0.70 µF . If a potential difference of 600 volt is applied to the combination, what charge will appear on each capacitor?
With & without trial & error method.
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Answered by
1
Answer:
q=CV
=0.70×600
Explanation:
=420 microcoulomb
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Here is your answer in the pic
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