Question

Six bags of cement, each marked 10 kg, actually contained the following weights of cement (in kg): ., ., ., ., ., . Find the probability that any of these bags chosen at random contains less than 10 kg of cement. ​

Answer 1

Step-by-step explanation:

the numbers are missing

kindly provide the weight of cements (., ., ., .,)

by the way the formula is

$\frac{number \: of \: favourable \: outcomes}{total \:number \: of \: outcomes \: }$

So

$\frac{numbers \: of \: cement \: bag \: with \: weight\: less \: than \: 10}{6}$

Answer 2

Answer:

2/6 = 1/3

Explanation:

This is the correct answer!

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