Question

Six balls of the same size are placed in a cylindrical water container (inner diameter 21cm) and are completely submerged in the water. What is the diameter of each sphere if the water rises by 2.5?.. please help fast someone.. I need it fast .​

Answer 1

Answer:

Given that, a solid hemisphere of diameter 10.5 cm is lowered into a cylindrical can of diameter 21 cm, containing water.

To find out: The rise in water level in the can.

Let h  

1

​

 be the rise in level of water.

We know that, the volume of a cylinder is πr  

2

h

∴  Volume of water rise when the sphere is immersed =πr  

2

h  

1

​

=π(10.5)  

2

h  

1

​

      −(1)

Volume of sphere =  

3

4

​

πr  

3

=  

3

4

​

π(5.25)  

3

     −(2)

The volume of the water rise = volume of the sphere

Hence, From (1) and (2), we get

π(10.5)  

2

h  

1

​

=  

3

4

​

π(5.25)  

3

 

⇒h  

1

​

=  

3×(10.5)  

2

 

4×(5.25)  

3

 

​

=  

330.75

578.81

​

 

⇒h  

1

​

=1.75 cm

Hence, the rise in level of water is 1.75 cm.

Step-by-step explanation:

I hope I answered you!!