Question

Six boys and six giris sit in a row randomly. The probability that boys and girls sit alternatively is?​

Answer 1

Answer:

Given 6 boys and 6 girls

There are 12 persons.

All of them can be seated in (12)! ways.

n(s)=(12)! ways where S is a sample space.

E= Event of the girls and boys to be seated alternately.

6 girls can be seated in 6! ways.

G  

1

​  

,G  

2

​  

,G  

3

​  

,G  

4

​  

,G  

5

​  

,G  

6

​  

 

There are 7 alternate places for 6 boys

6 boys can be seated in 7 places in  

7

P  

6

​  

 ways.

∴n(E)=6!.  

7

P  

6

​  

=  

(7−6)!

6!7!

​  

=6!.7!

∴ The required probability =  

n(S)

n(E)

​  

 

=  

12

6!7!

​

Step-by-step explanation:

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