six boys and six girls sit in the row. What is the probability that the boys and girls sit alternately
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6÷6=1
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RiddhiK11:
the answer is 1/462
I got the way how to do it thank you
probability =2(6!)(6!)/12!=1/462
12 members can be arranged in 12! ways. favourable events (m) =2*6!*6! then probability of success =m/n=2*6!*6!/12!=1/462
thank you
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