Question

Six cell emf 2V and the internal resistance 0.015 ohm are joined in a series provide supply to a resistance of 8.5 ohm what are the current drawn from the supply on terminal resistance

Answer 1

Dear Student,

◆ Answer -

I = 1.397 A

V = 11.87 V

◆ Explaination -

# Given -

n = 6

E = 2 V

r = 0.015 ohm

R = 8.5 ohm

# Solution -

For battery of 6 cells -

E' = nE = 6×2 = 12 V

r' = nr = 6×0.015 = 0.09 ohm

Current drawn from the supply is -

I = E' / (r' + R)

I = 12 / (0.09 + 8.5)

I = 12 / 8.59

I = 1.397 A

We can also calculate voltage across terminal resistance as -

V = I.R

V = 1.397 × 8.5

V = 11.87 V

Hope this helps you...