Physics, asked by shantanumahato9160, 8 months ago

Six charges each equal to +Q are placed at corners of regular hexagon of side (l) the electric potential and electric field at point p where diagonals intersect are

Answers

Answered by bhargav5897
0

Explanation:

The electric potential at the intersection of the diagonals PP is the sum of the electric potentials from all the point charges. As a regular hexagon is composed of equilateral triangles all these point charges have the distance xx from the point PP.

VE(P)=14πϵ0(6Qx)=3Q2πϵ0xVE(P)=14πϵ0(6Qx)=3Q2πϵ0x.

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