Question

Six charges q ,q q, -q , -q ,q are to be arranged on the vertices of a regular hexagon PQRSTU such that the electric field at centre is double the field produced when only charge 'q' is placed at vertex R. The sequence of charges from P to Q is
A) q . -q , q ,q -q , -q B)q ,q q,-q,-q ,-q
C)-q, q , q , -q , -q , q C)-q , q , q , q , -q , -q

Answer 1

Answer:

Explanation:

When q and q are one opp. sides, they will cancel out each other's field. So in case of q, -q, q, q, q, -q : 1 pair of q and q cancel out and other two pairs of   q,-q will form field of 2q charge.(superposition principle).

These two pair's electric fields will be at an angle 120 degrees, so their resultant will be equal to the magnitude of the individual vectors(since both have same magn.).

Answer 2

Explanation:

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