Question

Six children are playing Hide & Seek in a
park and were standing at different


position such that P is 9m towards the
north of T. Q is 4 m to the west of o, who
is 12 m to the east of T. U is 6 m to the
south of Q. R is 3m to the north of O.
Then few of them moved and their new
positions are denoted by adding (*) to
their respective names. P moved 5m
towards east. O moved 3 m towards the
east. Q moved 5 m towards the north.
What is the shortest distance between T
and U?​

Answer 1

Answer:

I think the shortest distance between T and U is

10 m

Answer 2

Given:

Total number of children=6

To find:

The shortest distance between T and U

Solution:

The shortest distance between T and U is 10m.

We can find the distance by following the given process-

We know that after a few children moved, T, U, and R did not change places.

So, T and U are still at the same distance from each other.

We are given that Q is to the East of T and U is to the South of Q.

The distance between T and Q=8m

The distance between Q and U=6m

Now, T, Q, and U form a right-angled triangle.

The length of the hypotenuse is the shortest distance between T and U.

We can find the distance by using the Pythagoras theorem.

Here, the distance between T and U is the hypotenuse, the distance between T and Q is the base and the distance between Q and U is perpendicular.

So, $base^{2} +perpendicular^{2} =hypotenuse^{2}$

Let the distance between T and U be X.

On putting the values, we get

$8^{2} +6^{2} =X^{2}$

64+36=$X^{2}$

100=$X^{2}$

X=10m

Therefore, the shortest distance between T and U is 10m.