Six children B, D, C, M, J and K are split into two groups of three each and are made to stand in two rows in such a way that a child in one row is exactly facing a child in the other row. M is not at the ends of any row and is to the right of J, who is facing C. K is to the left of D, who is facing M. Which of the following groups of children is the same row?
Answers
Step-by-step explanation:
BMJ
KDC
THIS is the answer
To Find :- Which of the following groups of children is the same row ?
A) BDC & MJK
B) BMD & BDC
C) MJK & BMD
D) BMJ & KDC
Solution :-
Let in first row three children are denoted by 1, 2 and 3 facing south also, three children in other row is denoted by 4, 5 and 6 facing north .
Statement 1) :- M is not at the ends of any row and is to the right of J who is facing C .
- M is in middle either at 2 or 5
- J, M , 3 => C, 5, 6
- 4, M , J => 1 , 2, C
Statement 2) :- K is to the left of D, who is facing M.
- D is facing M
- J, M , 3 => C, D, 6
- 4, M , J => 1 , D, C
- In C, D , 6 = K is left of D = C, D , K . Then, Left B will be at 3 . => JMB = CDK
- Or, BMJ = KDC .
therefore, from given options (D) BMJ & KDC is correct answer .
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