six coins are tossed probability of getting two to four head using a normal distribution is
Answers
Answer:
To begin with, we calculate the total number of possibilities that arise from tossing a coin 6 times . On each toss , we have 2 possibilities - a head or a tail. This gives us
2*2*2*2*2*2 = 64 possibilities
Now let's list out the desirable outcomes.
Having 4 heads
H H H H T T - This is one example of the above outcome. Something like
H H H T H T would also be equally likely and would be a desirable outcome. Thus to calculate all such permutations
6!/4!∗2!=15ways
Here , 6 is the total number of objects while 2 and 4 are the total number of identical objects.
2. Having 5 heads
H H H H H T- The total number of permutations with this mixture of heads and tails is
6!/5!∗1!=6
3. All 6 heads
H H H H H H - There happens to be only one way in which such a mixture can be arranged.
So therefore , calculating the probability
No of desired outcomes / No of total outcomes
15+6+1/64=11/32
0.343
Answer:
2/6
Step-by-step explanation:
F(e) = total no. of coins tossed =6
F(n) = total no. of head came = 2to 4
F(q) = total no. of coins tossed / total no. of head came = 2/6 = 1/3