Six coins are tossed simultaneously. Find the probability of getting:
1. 3 heads
2. No heads
3. atleast one head
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3heads:3÷13
no heads:3÷6
at least 1 head:1÷12
no heads:3÷6
at least 1 head:1÷12
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As 6 coins are tossed, total outcomes are 64.
1.P[3 heads]=20/64
=5/16
2.P[no heads]=1/64
3.P[At least one head]=63/64
1.P[3 heads]=20/64
=5/16
2.P[no heads]=1/64
3.P[At least one head]=63/64
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