Question

six consecutive numbers add up a total of 69. Which is the highest number?

Answer 1

Answer:

14.

Step-by-step explanation:

Let the required consecutive numbers are a - 3 , a - 2 , a - 1 , a , a + 1 and a + 2.

Here, the highest number is a + 2.

According to the question: sum of these numbers is 69.

⇒ ( a - 3 ) + ( a - 2 ) + ( a - 1 ) + a + ( a + 1 ) + ( a + 2 ) = 69

⇒ a - 3 + a - 2 + a - 1 + a + a + 1 + a + 2 = 69

⇒ 6a - 3 = 69

⇒ 6a = 69 + 3

⇒ 6a = 72

⇒ a = 72 / 6

⇒ a = 12

   Hence the highest number is a + 2 = 12 + 2 = 14.

Answer 2

AnSwEr :-

• Highest number is 14

GiVeN : -

• Sum of six consecutive numbers = 69

To FiNd : -

• Highest number

SoLuTiOn : -

Let the

First number be x

Then,

Second Number = (x +1)

Third Number = ( x + 2)

Fourth Number = (x +3)

Fifth number = ( x + 4)

Sixth number = (x + 5)

Now,

According to Question :-

We get,

=> x + (x + 1) + (x + 2) + (x + 3) + (x + 4) + (x + 5) = 69

=> 6x + 15 = 69

=> 6x = 69 - 15

=> 6x = 54

=> x = 54/6 = 9

Hence,

Highest Number is ( x + 5) = 9 + 5 = 14