Six dice are tossed together. What is the probability of getting the same face in all the dice?
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Hi,
n(S) = 46,656
Let A be the event of getting the same face in all the dice.
A ={(1,1,1,1,1,1),(2,2,2,2,2,2),(3,3,3,3,3,3),(4,4,4,4,4,4,),(5,5,5,5,5,5),(6,6,6,6,6,6)}
n(A) = 6
P(A) = n(A)/n(S)
= 6/46,656
= 1/7,776
Hope it helps you. Mark it as brainiest if it helps.
n(S) = 46,656
Let A be the event of getting the same face in all the dice.
A ={(1,1,1,1,1,1),(2,2,2,2,2,2),(3,3,3,3,3,3),(4,4,4,4,4,4,),(5,5,5,5,5,5),(6,6,6,6,6,6)}
n(A) = 6
P(A) = n(A)/n(S)
= 6/46,656
= 1/7,776
Hope it helps you. Mark it as brainiest if it helps.
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