Question

Six equal resistance are connected between points P,Q,R as shown in the figure.Then the resistance will be

Answer 1

Explanation:

The combination of resistances is shown in figure.

Maximum resistance will be between P and Q.

R

PQ

=

R+

3

R

+

2

R

R(

3

R

+

2

R

)

=

11R/6

5R

2

/6

=

11

5R

R

QR

=

11R/6

2

R

(R+

3

R

)

=

11R/6

2R

2

/3

=

11

4R

R

PR

=

11R/6

3

R

(R+

2

R

)

=

11R/6

R

2

/2

=

11

3R

.

Hence, the maximum value lies between P and Q.