Question

Six equal resistances of 2Ω each are connected to form the sides of a hexagon ABCDEF.

Calculate the resistance offered by the combination of the current that enters at B and

leaves at E.​

Answer 1

Answer:

Similarly equivalent resistance R2 of the group (AF, FE, ED)

= 2Ω + 2Ω + 2Ω = 6Ω

As the two groups are in parallel, we have

1/R = 1/R1 + 1/R2 = 1/6 + 1/6 = 2/6

Where R is the equivalent resistance of the whole combination.

∴ R = 6/2Ω or 4.5Ω

Explanation:

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