Question

Six faces of a die are shown:A,B,C,D,E,F the die is rolled once.to find the probability that C appears on upper face,fill in the boxes.therefore,n(a)=?

Answer 1

Answer:

1

Step-by-step explanation:

• S={A,B,C,D,E,F}
• (S)=6
• 'A' is an event where C appears on the upper face.
• A={C}
• n(A)=1

Answer 2

1/6  is the probability that C appears on upper face if Six faces of a die are A,B,C,D,E,F

Given:

• Six faces of a die are A,B,C,D,E,F
• The die is rolled once

To find:

• the probability that C appears on upper face

Solution:

• Probability of an event  = n(E)/n(S)  
• n(E) = number of possible outcome of event
• n(S) = number of possible sample space outcome

Step 1:

Count number of sample space

S = { A , B , C , D , E , F}

n(S) = 6

Step 2:

Assume that X is the event that C Appears on upper face

X = { C}

n(X) = 1

Step 3:

Find P(X) , the probability that C appears on upper face

P(X) = n(X)/n(S)

P(X) = 1/6

Hence 1/6  is the probability that C appears on upper face,