Business Studies, asked by goutham2918, 4 months ago

Six friends have their birthdays either on the 1st or 5th in the months of January ,February and March in the same year

Answers

Answered by raksblossoms
0

Answer

Given,

Age of 'D' = 38 years

Age of 'C' = Half the Age of D

Age of 'B' = Trice the age of 'C'

Age of 'A' = 20 years less than Age of 'B'.

To Find :-

Age of 'B'.

Solution :-

Given,

1)Age of 'C' = Half the Age of 'D'

Age of 'D' = 38 Years.

\sf\implies Age of 'C' = \dfrac{38 Years}{2}⟹Ageof

C

=

2

38Years

Age of 'C' = 19 years.

\sf\therefore Age of C = 19Years∴AgeofC=19Years

2) Age of 'B' = Thrice the Age of 'C'

Age of 'C' = 19 Years

\sf\implies Age of 'B' = 3 \times 19 Years⟹Ageof

B

=3×19Years

Age of 'B' 57 Years

\sf\therefore Age of 'B' = 57 Years∴Ageof

B

=57Years

3) Age of 'A' = 20 years less than Age of 'B'

Age of 'B' = 57Years

Age of 'A' = 57Years - 20Years

Age of 'A' = 37Years

\sf\therefore Required is Age of 'B' = 57years∴RequiredisAgeof

B

=57years

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