Question

six identical circles are cut from a rectangular piece of a paper . (a)what is radius of each cube .(b)find the remaining area of the paper

sides 14cm and 21 cm​

Answer 1

Answer:

first paper was 6 cm and sec paper was 7cm and

Answer 2

Radius of each circle is 3.5 cm and the remaining area of the paper is 63 cm².

Step-by-step explanation:

Six identical circles are cut from a rectangular piece of a paper.

Length of a rectangular piece of paper = L = 21 cm

Width of the rectangular piece of paper = W = 14 cm

Area of the rectangular piece of paper  = L x W = 21 x 14 = 294 cm²

a) Sum of the diameters of three circles along length side = 21 cm

Sum of the diameter of two circles along width side = 14 cm

Diameter of a circle = sum of diameters of three circles along length side - sum of the diameters of two circles along width side = 21 - 14 = 7 cm

So, radius of a circle = $\frac{diameter}{2} = \frac{7}{2}$ = 3.5 cm

b) Area of a circle = $\pi r^{2}$   Where r = radius

Area of a circle = $\frac{22}{7}\times 3.5^{2}$ = 38.5 cm²

Area of six circles = 6 x 38.5 = 231 cm²

Remaining area of the paper = Area of a rectangular paper - Area of six circles

Remaining area of the paper = 294 - 231 = 63 cm²

Hence, radius of each circle is 3.5 cm and the remaining area of the paper is 63 cm².