Six identical conducting rods are joined as shown in figure. Points A and D are maintained at temperatures 200ºC and 20ºC respectively. Then temperature of junction B will be - A) 120ºC (B) 100ºC (C) 140ºC (D) 80ºC
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answer : option (C) 140°
explanation : Let R is thermal resistance of each rod.
first of all, find equivalent thermal resistance between B and C.
[ using electrical concepts to find equivalent thermal resistance cause both concepts are similar.]
so, Req = R
now, thermal resistance between A and B = R
thermal resistance of B and D = R + R = 2R
now heat flows through A and B = heat flows through B and D
so, change in temperature between A and B/thermal resistance between A and B = change in temperature between B and D/thermal resistance between B and D
or, (200 - T)/R = (T - 20)/2R
or, 2(200 - T) = T - 20
or, 400 - 2T = T - 20
or, 3T = 420
or, T = 140
hence, temperature of junction B will be 140°C
option (C) is correct choice .
explanation : Let R is thermal resistance of each rod.
first of all, find equivalent thermal resistance between B and C.
[ using electrical concepts to find equivalent thermal resistance cause both concepts are similar.]
so, Req = R
now, thermal resistance between A and B = R
thermal resistance of B and D = R + R = 2R
now heat flows through A and B = heat flows through B and D
so, change in temperature between A and B/thermal resistance between A and B = change in temperature between B and D/thermal resistance between B and D
or, (200 - T)/R = (T - 20)/2R
or, 2(200 - T) = T - 20
or, 400 - 2T = T - 20
or, 3T = 420
or, T = 140
hence, temperature of junction B will be 140°C
option (C) is correct choice .
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