Six light bulbs are connected in parallel to a 9 v battery. Each bulb has a resistance of 3 . What is the potential difference across each bulb?
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Explanation:
resistance of each bulb=3 ohm
parallel resistance =1/r^p=1/R1+1/R2+1/r3+1/r4+1/r5+1/r6
=1/3×6=2ohms
now v=9 and
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