Math, asked by khanmohammed419, 1 year ago

Six missile launchers start operating together, firing the missiles at an interval of 5, 6, 8, 9, 10, and 12 seconds
respectively. How many times will they fire together in two hours of firing excluding the one at the start?
(a) Not even once
(b) 8 times
(c) 16 times
(d) 20 times​

Answers

Answered by ramesh08pune
0

Answer:

20 times

Step-by-step explanation:

12346randmly

so ×10÷5=

Answered by IamIronMan0
0

Answer:

20

Step-by-step explanation:

Calculate LCM

5 , 6 , 8 , 9 and 10 = 360secs

In 2 hrs = 3600 × 2 seconds

so the will attack

 \frac{3600 \times 2}{360}  = 20

20 times togather

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