Math, asked by Preetlotey96, 6 months ago

six new employees, two of whom are married to each other, are to be assigned six desks is made randomly , what is the probability that this person will have non-adjacent desks ​

Answers

Answered by ShashwatTopre2004
4

Answer:

Step-by-step explanation:

Total new employees = 6

So, they can be arranged in 6! ways  

∴ n(S) = 6! = 6 × 5 × 4 × 3 × 2 × 1 = 720

 

Two adjacent desks for married couple can be selected in 5 ways i.e. (1, 2), (2, 3), (3, 4), (4, 5), (5, 6)

Married couple can be arranged in the two desks in 2! ways

Other four persons can be arranged in 4! ways  

So, number of ways in which married couple occupy adjacent desks

= 5 × 2! × 4!

= 5 × 2 × 1 × 4 × 3 × 2 × 1

= 240

 

So, number of ways in which married couple occupy non – adjacent desks = 6! – 240

= (6 × 5 × 4 × 3 × 2 × 1) – 240

= 720 – 240

= 480 = n(E)

Required Probability = Number of favourable outcome/Total Number of Outcomes

= n(E)/n(S)

=480/720

=2/3

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