Six new employees,two of whom are married to each other,are to be assigned six desks that are lined up in a row.If the assignment of employees to desks is made randomly,what is the probability that the married couple will have non adjacent desks?
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Required probability =
Given six employees
Two are married to each other.
Tital number of outcomes they can sit randomly in a row n(S)=6!
Now probability of non adjacent desks =1-probability of adjacent desks
Let us find the probability of adjacent desks.
Step 2:
There are two couples
Number of outcomes of random arrangement of employees =5!
Consider 1 couple as 1 unit and arrangement of couple =2!
(ie) if a couple is AB then the seating arrangement can be AB or BA.
Number of favorable outcomes n(E)=
Step 3:
Required probability =
Step 4:
Probability of non-adjacent desks =1-probability of adjacent desks
Hence (C) is the correct answer.
answered Jul 7, 2014 by sreemathi.v
Required probability =
Given six employees
Two are married to each other.
Tital number of outcomes they can sit randomly in a row n(S)=6!
Now probability of non adjacent desks =1-probability of adjacent desks
Let us find the probability of adjacent desks.
Step 2:
There are two couples
Number of outcomes of random arrangement of employees =5!
Consider 1 couple as 1 unit and arrangement of couple =2!
(ie) if a couple is AB then the seating arrangement can be AB or BA.
Number of favorable outcomes n(E)=
Step 3:
Required probability =
Step 4:
Probability of non-adjacent desks =1-probability of adjacent desks
Hence (C) is the correct answer.
answered Jul 7, 2014 by sreemathi.v
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