Six particles are situated at the corners of a regular hexagon of side a and each particle move with a constant speed v in a direction towards the particle at the next corner. calculate the time the particle will take to meet each other.
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Given :
Particle A moves towards B with a speed V m/s
.Let us calculate the speed of B
:B is also moving with velcoity V along Bc direction.
Hence velocity component along BC:
Vcos60
=V/2
Relative speed of particle A with respect B =V-V/2
=V/2
To travel a distance a , time taken by the particle:
Time= Distance/ Speed
=a/(V/2)
=2a/V
Particle A moves towards B with a speed V m/s
.Let us calculate the speed of B
:B is also moving with velcoity V along Bc direction.
Hence velocity component along BC:
Vcos60
=V/2
Relative speed of particle A with respect B =V-V/2
=V/2
To travel a distance a , time taken by the particle:
Time= Distance/ Speed
=a/(V/2)
=2a/V
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