Question

six paving stones are arranged in a square array as shown in the figure if each stone has the length 20 CM greater than its width find.
1. dimension of each stone
2. the area of the ground space that the stones are occupying
3. the perimeter of the same ground space ​

Answer 1

Answer:

Step-by-step explanation:

Since the stones are arranged in square array, then

Length = Breadth (property of a square)

i.e. 2 * (x + 20) = 3 * x

i.e. 2x + 40 = 3x

i.e. x = 40cm

1. Hence, the dimension of each stone is 40,60 cm.

2. Total area of ground space occupied

= Total length * Total Breadth

= (3 * 40) * (2 * 60)

= 120 * 120

= 14400 sq.cm

3. Perimeter of ground space

= 4 x Length

= 4 * (3 * 40)

= 4 * 120

= 480 cm

Answer 2

Answer:

Since the stones are arranged in square

array, then

Length = Breadth (property of a square)

i.e. 2 * (x + 20) = 3 * x

i.e. 2x+40= 3x

i.e. x 40cm

1. Hence, the dimension of each stone is

40,60 cm.

2. Total area of ground space occupied

= Total length * Total Breadth

= (3 * 40) * (260)

= 120 * 120

= 14400 sq.cm

3. Perimeter of ground space

= 4 x Length

= 4* (3 * 40)

= 4* 12

=480