Question

Six point masses each of mass m are placed at the
vertices of a regular hexagon of side 1. The force
acting on any of the masses is​

Answer 1

Answer:

[(5(3^(1/2))+1)Gm^2]/4(3^(1/2))

Explanation:

See the images. I attached totally 4 images of the solution. Just mentioning because you may miss the other two attachments. If you find any difficulty in viewing the image just zoom in because I needed to capture the whole page.