Six rectangles each with a common base width of 2 have lengths of 1,4,9,16,25, and 36. What is the sum of the areas of the six rectangles?
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1. 2*1=2
2. 2*4=8
3. 2*9=18
4. 2*16=32
5. 2*25=50
6. 2*36=72
7. 72+50+32+18+8+2=182
2. 2*4=8
3. 2*9=18
4. 2*16=32
5. 2*25=50
6. 2*36=72
7. 72+50+32+18+8+2=182
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Area of any rectangle = length*breadth
The sum of areas of the six rectangles = Area of R1 + R2 + R3 + R4 + R5 + R6
⇒(1×2) + (4×2) + (9×2) + (16×2) + (25×2) + (36×2)
⇒2 + 8 + 18 + 32 + 50 + 72
⇒182 sq.units
The sum of areas of the six rectangles = Area of R1 + R2 + R3 + R4 + R5 + R6
⇒(1×2) + (4×2) + (9×2) + (16×2) + (25×2) + (36×2)
⇒2 + 8 + 18 + 32 + 50 + 72
⇒182 sq.units
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