Six square plots are connected end to end to obtain a rectangular plot of area 726 m2. If we taken by
what factor is the perimeter of this plot more than that of the circumference of a circle of radius 10m?
Answers
Step-by-step explanation:
bro u just have to find the perimeter of rectangle and circle
let widthside =x
length side=6x
area of rectangle
l×b
terefore
x × 6x=726
x=11
perimeter of rectangle
2(l+b)
2(x+6x)
2(11+6×11)
154
area of circle ⭕
2πr
2×3.14×10
62.8
Question :
Six square plots are connected end to end to obtain a rectangular plot of area 726 m^2. If we take π = 22/7, by what factor is the perimeter of this plot more than that of circumference of a circle of radius 10 m?
Answer :
Factor by which the perimeter of the rectangular plot is more than that of circumference of a circle is 2.45.
Given :
Area of rectangular plot = 726 m
π = 22/7
Radius of a circle = 10m
To find :
Factor by which the perimeter of the rectangular plot is more than that of circumference of a circle
Solution :
Area of Rectangle = 726m^2
Rectangle is composed of 6 square plots
Area of a square plot = 726/6 = 121 m^2
Side of the square plot = √121
= 11m
Now length of the rectangle will be 6 × 11 (since square plots are laid side by side) = 66 m
Perimeter of rectangle = 2(length + breadth)
2(11 + 66) = 154 m
Circumference of circle of radius 10 m = 2 π r = 2 × 22/7 × 10
= 440/7
= 62.85
By factor the perimeter of Rectangular plot is more than circular plot = Perimeter of rectangular plot / Circumference of circle
= 154/62.85
= 2.45
Hence, Factor by which the perimeter of the rectangular plot is more than that of circumference of a circle is 2.45.
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