Question

six the year ago ratio of age of Shahn and mohan 6:5. four the year hence ratio of their age 11:10 What is rratio of parent age.​

Answer 1

Step-by-step explanation:

Let the ages of Kunal and Sugar 6 years ago be 6x and 5x years respectively.

Then, (5x+6)+4(6x+6)+4=1011

⇒10(6x+10)=11(5x+10)

⇒5x=10

⇒x=1

∴ Sagar's present age = (5x + 6) = 16 years.

Answer 2

Answer:

• The ratio of their present ages is 9 : 8

Step-by-step explanation:

Given:-

• six the year ago ratio of age of Shahn and mohan 6:5
• four the year hence ratio of their age 11:10

To Find:-

• What is ratio of their present ages.​

Assumptions:-

• Let the present age of Shahn six years ago be 6x
• Let the present age of Mohan six years ago be 5x

The present ages will be :-

• The present of of Shahn will be 6x + 6 years
• The present age of Mohan will be 5x + 6 years

The age after four years will be :-

• The age of Shahn after 4 years = 6x + 10
• The age of Mohan after 4 years = 5x + 10

According to the question:-

$\longrightarrow \tt \dfrac{6x+ 10}{5x + 10} = \dfrac{11}{10}$

Cross Multiplying we get :-

$\longrightarrow \tt 10 ( 6x + 10 ) = 11 ( 5x + 10 )$

$\longrightarrow \tt 60x + 100 = 55x + 110$

$\longrightarrow \tt 60x - 55x = 110 - 100$

Solving it further we get :-

$\longrightarrow \tt 5x = 10$

$\longrightarrow \tt x = \cancel\dfrac{10}{5}$

$\longrightarrow \tt {\blue{\boxed{\frak{ x = 2}}}\pink\bigstar}$

The present ages of them will be:-

• Shahn' s age = 6x + 6 = 18 years
• Mohan's age = 5x + 6 = 16 years

The present ratio will be :-

$\longrightarrow \tt 18 : 16$

$\longrightarrow {\boxed{\tt {9 : 8}}}$

Therefore :-

• The ratio of their present ages is 9 : 8

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