Question

six year before the age of mother was equal to the square of a son's age 3 years hence her age will be thrice the age of person then find the present age of mother and son

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Answer 1

Let age of son 6 years before be x

then mother's age = x

2

then, persent age son =x+6

mothers age =x

2

+6

After 3 year,

son =x+6+3=x+9

mother =x

2

+6+3=x

2

+9

A.T.Q

x

2

+9=3(x+9)

x

2

+9=3x+27

x

2

−3x−18=0

x

2

−6x+3x−18=0

x(x−6)+3(x−6)=0

(x+3)(x−6)=0

x=6 (-3 will neglect)

Persent age of mother = x

2

+6⇒36+6=42

Son = x+6=6+6=12

Answer 2

Answer:

present age of son =12years

present age of mother=42years

Step-by-step explanation:

six years ago

son's age=x

mother's age=x∧2

after 3 years

son's age=x+6+3= x+9

mother'sage=x∧2+6+3= x∧2+9

A.T.Q

x∧2+9 = 3(x+9)

hope you can solve now......