Question

six year before the age of mother was equal to the square of her son's Age 3 years hence her age will be thrice the age of his son then find the present ages of the mother and son

Answer 1

Hello dear here is ur ans :-

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Answer.

Son =12 years
Mother =42 years

Explanation.

Six year ago let's the son age = x
Mother = x^2

Present ages now :

Son = x + 6
Mother = x^2 + 6

3 years later :

Son = x +6 + 3 = x + 9
Mother = x^2 + 6 + 3 = x^2 + 9

Solving x -

X^2 + 9 = 3 ( x + 9)
X^2 + 9 = 3x + 27
X^2 - 3x - 18 = 0
(x - 6)(x+3) = 0
X=6 or x = -3

Take x = 6. As the other value is (-value)

Finding their present age -

Son = x + 6 = 6 + 6 =12 years.
Mother = x^2 + 6 =(6)^2 + 6 = 42 years.

Hence :

Son = 12 years.
Mother = 42 years.

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