Question

Six years ago, a father was 5 times as old as his son. Six years hence the sum of their ages will be 72 years. Taking the present ages of the father and the son to be x and y respectively,
(i). the simultaneous equations formed
(ii). father's age
(iii). son's age​

Answer 1

Answer:

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Step-by-step explanation:

(i) fathers age is 5 times more than son

take fathers age to be x and sons age to be y

so, x=5y.

now, sum of their ages is 72, so,

5y+y = 72

6y = 72

y = 72/6 = 12

(ii) fathers age is 5y, so, 5×12=60

(iii) sons age is y, so, 12

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