SIX YEARS AGO , A FATHER WAS SEVEN TIMES AS OLD AS HIS SON . AFTER SIX YEARS , HE WILL BE THREE TIES AS OLD AS HIS SON . THE SUM OF THEIR PRESENT AGE IS ?
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Let us assume, father's present age is x years and son's present age is y years.
Given, six years ago:
x - 6 = 7(y - 6)
x - 6 = 7y - 42
7y - x = 36 -------------1
Also given, After 6 years:
x + 6 = 3 ( y + 6)
x + 6 = 3y + 18
x - 3y = 12 -------------2
Add equation 1 and equation 2
4y = 48
y = 12 years
Substitute the value of y in equation 1
7 * 12 - x = 36
84 - x = 36
x = 48 years.
The sum of the present age of father and present age of son = 48 + 12 = 60 years.
Given, six years ago:
x - 6 = 7(y - 6)
x - 6 = 7y - 42
7y - x = 36 -------------1
Also given, After 6 years:
x + 6 = 3 ( y + 6)
x + 6 = 3y + 18
x - 3y = 12 -------------2
Add equation 1 and equation 2
4y = 48
y = 12 years
Substitute the value of y in equation 1
7 * 12 - x = 36
84 - x = 36
x = 48 years.
The sum of the present age of father and present age of son = 48 + 12 = 60 years.
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