Question

Six years ago A was half of B's age If the ratio of their present age is 2:3 what is the total of their present age

Answer 1

Answer:

Refers to attachment :)

xD sorry! I miss write the ratio's (2:3) as (3:4).

But you can easily solve question by attaining same method. Try it once by taking accurate ratio(2:3).

Thanks!! khushi♡

Answer 2

Answer:

A's age = 9 years

B's age = 12 years

Step-by-step explanation:

Given:

• Six years ago A was half of B's age
• Their present ratio is 2:3

To Find: Total sum of their present ages

Solution: Let present ages of two be A and B

†According to the question†

$\small\implies{\sf }$ A:B = 2:3

$\small\implies{\sf }$ 3A = 2B .......(1)

or,

$\small\implies{\sf }$ A–6 = B–6/2

$\small\implies{\sf }$ 2A–12 = B–6

$\small\implies{\sf }$ 2A–B = –6+12

$\small\implies{\sf }$ 2A–B = 6

$\small\implies{\sf }$ 2A= 6+B.........(2)

†Now, Putting the value of equation (2) in equation (1) , We got

$\small\implies{\sf }$ 2(6+B) = 3B

$\small\implies{\sf }$ 12+2B = 3B

$\small\implies{\sf }$ 12 = 3B–2B

$\small\implies{\sf }$ 12 = B

Hence , Age of B is 12 years

And, Age of A = 6+12/2 = 18/2 = Years