Question

Six years ago raj's father's age is 6 times the age of raj. The difference of present ages is 35. What is the sum of their present ages?

Answer 1

HEY Buddy...!! here is ur answer

Let, the present age of Raj's father and Raj is x and y years respectively.

According to the question :

(x–6) = 6(y–6) => x–6y = –30....(1)

x–y = 35.......(2)

On subtracting :

–5y = –65

=> y = 13 years

On putting the value of y in equation (2)

x–13 = 35 => x = 48 years

x+y = 13+48 = 61 years

So, the sum of their present ages will be 61 years.

I hope it will be helpful for you...!!

THANK YOU ✌️✌️

Answer 2

Let the present age of Raj be Y years.

The present age of Raj's father be X years.

Given relation between the ages of Raj and Raj's father is

Raj's father age is 6 times the age of Raj

$x = 6y$

Given the difference of their present ages is 35.

$x - y = 35$

We need to find the sum of their present ages.

By solving the two relations we have,

$x - y = 35 \\ 6y - y = 35 \\ 5y = 35 \\ y = 35 \div 5 \\ y = 7$

Therefore, present age of Raj is 7 years.

Present age of Raj's father is

$x = 6y \\ = 6 \times 7 \\ = 42$

Therefore, present age of Raj's father is 42 years.

We need to find the sum of their present ages.

$x + y = 42 + 7 \\ = 49$

Therefore, the sum of their present ages is 49 years.

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