Six years ago the age of a person was two years more than five times the age of his son four years hence his age will be two years less than three times age of his son
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Let the age of father be x years
Let the age of son be y years
X-6=5(y-6)+2
X-5y=-22
X+4=3(y+4)-2
X-3y=6
On solving we get x=48 and y=14
Let the age of son be y years
X-6=5(y-6)+2
X-5y=-22
X+4=3(y+4)-2
X-3y=6
On solving we get x=48 and y=14
Answered by
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The complete question is as follow:--
Six years ago age of person was two more than five times age of his son and four years hence his age will be two years less than three times age of his son.Find the present ages of son and the person?
Let age of son be x years
Let age of man be y years
Six years ago man age =y-6 years
Son age =x-6 years
Acc.to question condition
(y-6)=5(x-6)+2
Age of son 4 years hence =x+4 year
Man age =y+4 years
Acc to condition
y+4=3(x+4)-2
On solving we have
Son present age =14 yrs
Man present age =48yrs
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