Question

Six years ago the ages of A and B were in the ratio of 4:3. Nine years from now, their ages will be in the ratio 7:6. Find their present age.

Answer with explanation and no spamming​

Answer 1

Answer:

A = 26 years

B = 21 years

Step-by-step explanation:

age of A six years ago = 4x

age of B six years ago = 3x

present ages :

A = 4x + 6

B = 3x + 6

Ages after 9 years

A = 4x + 6 + 9

B = 3x + 6 + 9

ATQ => $\frac{4x + 6 + 9}{3x + 6 + 9}$ = $\frac{7}{6}$

=> 6(4x +6 +9) = 7(3x+6+9)

=> 24x + 36 + 54 = 21x + 42 + 63

=> 24x + 90 = 21x + 105

=> 24x - 21x = 105 - 90

=> 3x = 15

=> x = 5

thus present ages

A=> 4x + 6 = 20+ 6 = 26 years

B => 3x + 6 = 15 + 6 = 21 years

Please mark it as the brainliest

Answer 2

Step-by-step explanation:

Answer:

A = 26 years

B = 21 years

Step-by-step explanation:

age of A six years ago = 4x

age of B six years ago = 3x

present ages :

A = 4x + 6

B = 3x + 6

Ages after 9 years

A = 4x + 6 + 9

B = 3x + 6 + 9

ATQ => \frac{4x + 6 + 9}{3x + 6 + 9}

3x+6+9

4x+6+9

= \frac{7}{6}

6

7

=> 6(4x +6 +9) = 7(3x+6+9)

=> 24x + 36 + 54 = 21x + 42 + 63

=> 24x + 90 = 21x + 105

=> 24x - 21x = 105 - 90

=> 3x = 15

=> x = 5

thus present ages

A=> 4x + 6 = 20+ 6 = 26 years

B => 3x + 6 = 15 + 6 = 21 years

Please mark it as the brainliest