Six years ago, the average age of A, B, C, and D was 30 years. When E joined them, the average of all the five becomes 40 years. The age of E is
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C) 45
(A−5)+(B−5)+(C−5)+(D−5)4 = 45
A+B+C+D−204 = 45
A+B+C+D = 180+20 = 200
Now A+B+C+D+E5 = 49
A+B+C+D+E = 245
A+B+C+D+E = 245 - 200 = 45
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I don't know the correct answer but I think it is 55
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