six years ago the ratio of ages of A&B was 1:3 and after six years the ratio becomes 2:3.find the sum of present age of A&B.
Answers
▪Assumptions :-
Let
Present age of A be = x years
and
Present age of B be = y years
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▪Given :-
1》Six years ago the ratio of ages of A & B was 1:3
2》After six years the ratio will be 2:3.
___________________________
▪To Calculate :-
Sum of present ages of A and B.
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▪Solution :-
《 Six years ago 》
Age of A = (x - 6) years
and
Age of B = (y - 6) years
According to the Given Condition:
《 After Six years 》
Age of A = (x + 6) years
and
Age of B = (y + 6) years
According to the Given Condition:
Subtracting {ii} from {i} we get,
Putting Value of y in {i} We get,
Hence ,
Present age of A = 10 years
and
Present age of B = 18 years
So,
___________________________
Given :-
Six years ago the ratio of ages of A&B was 1:3 and after six years the ratio becomes 2:3
To Find :-
Sum of present ages
Solution :-
Six years ago
A - 6/B - 6 = 1/3
3(A - 6) = 1(B - 6)
3A - 18 = B - 6
3A - B = 18 - 6
3A - B = 12 (1)
Now
A + 6/B + 6 = 2/3
3(A + 6) = 2(B + 6)
3A + 18 = 2B + 12
3A - 2B = 12 - 18
3A - 2B = -6
Subtract both
B = 18
Using 1
3a - 18 = 12
3a = 30
a = 30/3
a = 10
Sum = 18 + 10 = 28 years