Math, asked by nittalapadma1140, 1 year ago

six years ago the ratio of the ages of dexter and debra was 6 : 5. four years hence the ratio of their ages will be 11 : 10. what is debra's present age?

Answers

Answered by NavaN11
1

Let x and y be the present ages of Dexter and Debra

So,

(x-6)/(y-6) = 6/5

5(x-6) = 6(y-6)

5x -30 = 6y - 36

5x - 6y = -6...............................1)

Now, As per second condition,

(x + 4)/ (y+ 4)= 11/10

10 (x +4) = (y +4) 11

10x + 40 = 11y + 44

10x - 11y= 4......................................2)

Multiplying equation 1) by 2 and then substracting it by 2) we get,

y = 12 + 4

y = 16

So,

Debra's present age is 16 years


siddhartharao77: Bro, small mistake. it is 6 years ago.
NavaN11: Yes Thankyou sir, can you also send me the correction link ?
Answered by siddhartharao77
0

Let the present age of Dexter be x years and Debra be y years.


Given that 6 years ago, their ages was in the ratio 6:5.


 = > \frac{x - 6}{y - 6} = \frac{6}{5}


= > 5(x - 6) = 6(y - 6)


= > 5x - 30 = 6y - 36


= > 5x - 6y = -6.



Given that After 4 years the ratio of their ages will be 11:10.


 = > \frac{x + 4}{y + 4} = \frac{11}{10}


= > 10(x + 4) = 11(y + 4)


= > 10x + 40 = 11y + 44


= > 10x - 11y = 4 -------- (2)



On solving (1) * 2 & (2), we get


= > 10x - 12y = -12


= > 10x - 11y = 4


----------------------


-y = -16


y = 16.




Therefore the present age of Debra is 16 years.



Hope this helps!

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