Question

Six years ago, the sum of ages of mother and father was 10 years less
than five times the sum of ages of their five children. At present, two
third the sum of ages of mother and father is seven less than times
the sum of present ages of children. Then, the sum of present ages of
the family is
​

Answer 1

Step-by-step explanation:

Let the present age of son be x.

Then, present age of father is (60−x).

According to the question,

⇒ (60−x)−6=5(x−6)

⇒ 54−x=5x−30

⇒ 54+30=5x+x

⇒ 84=6x

⇒ x= 6/84⇒ x=14∴ Son's age after 6 years =(x+6)years

=(14+6)years

=20years.