Math, asked by rsreekanthaadhi, 5 months ago

Six years back age of Munir was 3time age of Mujib after four year age of Munir becomes twice the ag
e of Mujib find the age of two of them​

Answers

Answered by taadarsh1986
0

let present age of munir,mujib=x,y respectively

six years before munir age=x-6

six years before mujib age=y-6

But according to problem,

==>x-6=3(y-6)

==>x-6=3y-18

==>3y-x=12------->eq1

two years before munir age=x-2

two years before mujib age=y-2

But according to problem,

==>x-2=2(y-2)

==>x-2=2y-4

==>2y-x=2------->eq2

eq1-eq2==>

3y-x-(2y-x)=10

y=10

substitute value of y in eq2:

2(10)-x=2

x=20-2

x=18

so,

age of munir,mujib are 10,18 respectively

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